((x^5/3y^1/3*y^7/4)/x^-2)^-2

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Solution for ((x^5/3y^1/3*y^7/4)/x^-2)^-2 equation:


D( x )

((((((x^5)/3)*y^1)/3)*y^7)/4)/(x^-2) = 0

x = 0

x^-2 = 0

((((((x^5)/3)*y^1)/3)*y^7)/4)/(x^-2) = 0

((((((x^5)/3)*y^1)/3)*y^7)/4)/(x^-2) = 0

((((((x^5)/3)*y)/3)*y^7)/4)/(x^-2) = 0

1/36*x^7*y^8 = 0 // : 1/36*y^8

x^7 = 0

x = 0

x = 0

x = 0

x^-2 = 0

x^-2 = 0

1*x^-2 = 0 // : 1

x^-2 = 0

x należy do O

x in (-oo:0) U (0:+oo)

(((((((x^5)/3)*y^1)/3)*y^7)/4)/(x^-2))^-2 = 0

(((((((x^5)/3)*y)/3)*y^7)/4)/(x^-2))^-2 = 0

1296*x^-14*y^-16 = 0 // : 1296*y^-16

x^-14 = 0

x należy do O

x belongs to the empty set

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